Find the error in C++ program

This C++ program is not compiling. What do you think is the error with the program?

#include<iostream>
using namespace std;
int main()
{
   int arr[10];
   arr={1,2,3,4,5,6,7,8};
   cout<<"arr[0]="<<arr[0];
   return 0;
}

Is the error due to

Not using printf
Initialising the array with only 8 elements instead of 10
Initialising array in the next statement instead of in definition.
None of the above

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By the way the correct answer is (3)

Comments

Polymorphism

You hear the term Polymorphism too frequently with object oriented languages. Along with Inheritance and Encapsulation, polymorphism is one of the corner stones of object oriented design. What is Polymorphism, exactly? Polymorphism is a mechanism by which you provide single interface for multiple methods. (poly - many, morph - form). In C++, polymorphism can be compile time or run-time. Compile time polymorphism is provided with the help of overloaded operators/functions and templates. Run time polymorphism is provided with the help of virtual functions and late binding. Late Binding: Connecting a function call to function body is called binding. Most functions use early binding where this binding happens before the program is run - during compile time. This is also called static binding. Late binding (also called dynamic binding) is when a function call is connected to function body at run time. This is done after looking at the type of the object. Late binding is ach

Operator Overloading

What is operator overloading ? Operator overloading is the process of customizing C++ operators for operands of user defined types. When you have two objects of a class- num1 and num2 , you can write a function to add them such as ans = add(num1,num2); That does not look neither simple nor intuitive. You would prefer to write ans = num1+num2; as you would write expressions for basic data types like integers, floats etc. This can be done using Operator overloading. Operator overloading lets you write such statements. That is, it lets you call your functions on objects using +, - ,* etc. + operator will call addition function on the object (when you write op. overloading function for +). * will call multiply on objects etc. Names of overloaded operator functions start with keyword operator followed by symbol of the operator. e.g. +, - etc. Unary operator functions take 0 parameters for members. The operand for these function is the object cal

Constant members of a Class

A constant is a value which can not be modified. As in C, we can have literal constants using #define and we can have enums and we can define a variable to be const . Let us look at const variables here. By declaring a variable as const , we ensure that it is not modified accidentally. Any modification to a constant will give a compilation error. A const should always be initialized while defining. In the program below, assignment to pi gives a compiler error because pi is defined as const and code is trying to modify this. int main () { const float pi = 22.0/7 ; int radius = 12 ; radius ++ ; /*ok*/ pi = 3.14 ; /*error*/ } Constant parameters to functions Even function parameters can be const ant. We have earlier discussed that making a reference parameter as constant will avoid the function from accidentally modifying the argument. void printnum ( int & n) { cout << n ++ ; } void printnum2 ( const int & n) { cout <&l

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